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IIT M FOUNDATION AN EXAM QDF3 13 Apr - 13 Apr 2025

MLT End Term17 questions50 marks6 MCQ · 6 SA · 5 MSQFoundation / afternoon / QDF3
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Q1MSQ2 marksselect all that apply
What is the role of the regularization term in ridge regression?
  1. It ensures that the dataset is normally distributed.
  2. It penalizes large coefficients to reduce overfitting.
  3. It forces more coefficients to be exactly zero, performing feature selection.
  4. It increases the variance of the model.
Q2MSQ2 marksselect all that apply
Which of the following conditions must be satisfied for a decision tree to be pure at a given node?
  1. The entropy of the node is maximum.
  2. The information gain at the node is negative.
  3. All samples at a node belong to the same class.
  4. The entropy of the node is 0.
Q3MCQ3 marks
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Q4MCQ3 marks
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Q5MCQ2 marks
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  1. Kernel PCA with a polynomial kernel of degree 2.
  2. Kernel PCA with a polynomial kernel of degree 3.
  3. Kernel PCA with a polynomial kernel of degree 4.
  4. Standard PCA
Q6MCQ1 mark
Weak learners used in the ensemble method typically perform slightly better than random guessing.
  1. TRUE
  2. FALSE
Q7MSQ3 marksselect all that apply
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  1. Model 1 will have a higher bias than Model 2.
  2. Model 2 will have a lower variance than Model 1.
  3. Model 1 is more likely to underfit.
  4. Model 1 is more likely to overfit.
Q8MSQ3 marksselect all that apply
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Q9MSQ4 marksselect all that apply
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Q10SA4 marks
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Q12SA4 marks
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Q13SA4 marks
The following dataset represents different weather conditions and the corresponding decision on whether a person chooses to play tennis: question figure The following dataset represents different weather conditions and the corresponding decision on whether a person chooses to play tennis:
Q14SA3 marks
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Q15SA3 marks
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Comprehension passage - the questions below it refer to this
Based on the above data, answer the given subquestions. question figure
Q16MCQ2 marks
Which classifier has the lower training error?
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Q17MCQ3 marks
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Answer key

  1. Q1 (MSQ, 2 marks): B
  2. Q2 (MSQ, 2 marks): C, D
  3. Q3 (MCQ, 3 marks): B
  4. Q4 (MCQ, 3 marks): A
  5. Q5 (MCQ, 2 marks): B
  6. Q6 (MCQ, 1 marks): A
  7. Q7 (MSQ, 3 marks): A, C
  8. Q8 (MSQ, 3 marks): B, D, E
  9. Q9 (MSQ, 4 marks): B, E
  10. Q10 (SA, 4 marks): 262.2 to 262.8
  11. Q11 (SA, 4 marks): 0.148 to 0.154
  12. Q12 (SA, 4 marks): 4
  13. Q13 (SA, 4 marks): 0.61 to 0.67
  14. Q14 (SA, 3 marks): 1
  15. Q15 (SA, 3 marks): 1
  16. Q16 (MCQ, 2 marks): A
  17. Q17 (MCQ, 3 marks): B

Concepts this paper tests

Auto-generated summary from the source site. Handy as a checklist; the lessons above explain each idea from scratch.

Here’s a structured summary of core topics, concepts, principles, and equations for the exam, followed by Mermaid knowledge graphs to visualize relationships.


Core Topics & Concepts

1. Linear & Regularized Regression

Key Insight:


2. Decision Trees & Entropy

Key Insight:


3. Clustering (Lloyd’s Algorithm / K-Means)


4. Dimensionality Reduction (PCA & Kernel PCA)


5. Ensemble Methods (AdaBoost)


6. Support Vector Machines (SVM)


7. Perceptron Algorithm


8. Kernel Methods (Kernel Regression)


9. Bayesian Inference (Beta-Binomial)


10. Neural Networks (Single-Layer)


11. Naïve Bayes


12. Logistic Regression


13. SVM Prediction


Graph 2: Unsupervised Learning

Graph 3: Ensemble & Bayesian Methods

Graph 4: Neural Networks

Graph 5: Probabilistic Models


Key Equations Summary

TopicEquation
Linear Regressiony=wTx+by = w^T x + b, Loss = 1n∑(yi−y^i)2\frac{1}{n} \sum (y_i - \hat{y}_i)^2
Ridge RegressionLoss = MSE + λ∑wj2\lambda \sum w_j^2
Lasso RegressionLoss = MSE + λ∑∣wj∣\lambda \sum |w_j|
EntropyH(S)=−∑pilog⁡2piH(S) = -\sum p_i \log_2 p_i
Information GainIG=H(parent)−∑∣Si∣∣S∣H(Si)\text{IG} = H(\text{parent}) - \sum \frac{|S_i|}{|S|} H(S_i)
SVM Dual Problemαi\alpha_i (Lagrange multipliers), f(x)=∑αiyiK(xi,x)f(x) = \sum \alpha_i y_i K(x_i, x)
Kernel PCAK(x,x′)=(xTx′+c)dK(x, x') = (x^T x' + c)^d (Polynomial)
AdaBoost Weight Updatewi←wi⋅eαt⋅I(yi≠ht(xi))w_i \leftarrow w_i \cdot e^{\alpha_t \cdot \mathbb{I}(y_i \neq h_t(x_i))}
Bayesian PosteriorBeta(α+heads,β+tails)\text{Beta}(\alpha + \text{heads}, \beta + \text{tails})
Logistic RegressionP(y=1)=σ(wTx)P(y=1) = \sigma(w^T x), σ(z)=11+e−z\sigma(z) = \frac{1}{1 + e^{-z}}
Naïve BayesP(y∣x)∝P(y)∏iP(xi∣y)P(y|x) \propto P(y) \prod_i P(x_i|y)