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IIT M FOUNDATION AN EXAM QDF4 01 Dec - 01 Dec 2024

MLF Quiz 215 questions40 marks12 MCQ · 3 MSQFoundation / afternoon / QDF4
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Q1MSQ3 marksselect all that apply
Note: BH is a conjugate transpose of B. question figure
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Q2MSQ3 marksselect all that apply
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Q6MCQ3 marks
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Q7MCQ3 marks
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  1. (3,7)
  2. (0.4, 1.8)
  3. (0,0)
  4. (-1,0)
Comprehension passage - the questions below it refer to this
Based on the above data answer the given subquestions. question figure
Q8MCQ2 marks
Which of the following options is/are true?
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Q9MCQ2 marks
Which of the following options is/are true ?
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Q10MCQ2 marks
Which of the following options is true?
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Comprehension passage - the questions below it refer to this
Based on the above data answer the given subquestions. question figure
Q11MCQ3 marks
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Q12MCQ3 marks
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Q14MSQ2 marksselect all that apply
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  1. M is an invertible matrix.
  2. M is a singular matrix.
  3. The determinant of M is 4.
  4. M is diagonalizable.
Q15MCQ2 marks
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  1. A is positive definite.
  2. A is positive semi-definite.
  3. A is negative definite.
  4. A is negative semi-definite.

Answer key

  1. Q1 (MSQ, 3 marks): B, C
  2. Q2 (MSQ, 3 marks): A, B, C
  3. Q3 (MCQ, 3 marks): B
  4. Q4 (MCQ, 3 marks): A
  5. Q5 (MCQ, 3 marks): A
  6. Q6 (MCQ, 3 marks): B
  7. Q7 (MCQ, 3 marks): B
  8. Q8 (MCQ, 2 marks): B
  9. Q9 (MCQ, 2 marks): D
  10. Q10 (MCQ, 2 marks): A
  11. Q11 (MCQ, 3 marks): A
  12. Q12 (MCQ, 3 marks): D
  13. Q13 (MCQ, 3 marks): A
  14. Q14 (MSQ, 2 marks): B, D
  15. Q15 (MCQ, 2 marks): B

Concepts this paper tests

Auto-generated summary from the source site. Handy as a checklist; the lessons above explain each idea from scratch.

Summary of Core Topics, Concepts, Principles, and Equations

Linear Algebra

  1. Matrices and Their Properties

    • Conjugate Transpose (Hermitian): BHB^H
    • Unitary Matrix: A†A=AA†=IA^\dagger A = A A^\dagger = I
    • Eigenvalues and Eigenvectors: Av=αvA \mathbf{v} = \alpha \mathbf{v}
    • Diagonalization: A=QΛQTA = Q \Lambda Q^T
    • Singular Value Decomposition (SVD): A=Q1ΣQ2TA = Q_1 \Sigma Q_2^T
    • Determinant: det(A)\text{det}(A)
    • Quadratic Forms: Q(x,y,z)=[xyz]M[xyz]Q(x, y, z) = \begin{bmatrix} x & y & z \end{bmatrix} M \begin{bmatrix} x \\ y \\ z \end{bmatrix}
  1. Matrix Types and Properties

    • Symmetric Matrix: M=MTM = M^T
    • Diagonal Matrix: All off-diagonal elements are zero.
    • Identity Matrix: Diagonal matrix with all diagonal elements equal to 1.
    • Upper Triangular Matrix: All elements below the main diagonal are zero.
    • Lower Triangular Matrix: All elements above the main diagonal are zero.
    • Singular Matrix: Determinant is zero.
    • Invertible Matrix: Determinant is non-zero.
    • Positive Definite and Semi-Definite Matrices
  1. Eigenvalue and Eigenvector Equations

    • Characteristic Equation: det⁡(A−λI)=0\det(A - \lambda I) = 0
    • Eigenvalue Magnitude for Unitary Matrices: ∣α∣=1|\alpha| = 1
  1. Principal Component Analysis (PCA)

    • Covariance Matrix: CC
    • Eigenvalues of Covariance Matrix: λ1,λ2\lambda_1, \lambda_2
    • Projections onto Principal Components

Optimization

  1. Gradient Descent Algorithm

    • Update Rule: xt+1=xt−ηt∂f∂xx_{t+1} = x_t - \eta_t \frac{\partial f}{\partial x}
    • Learning Rate: ηt=1t2\eta_t = \frac{1}{t^2}
    • Partial Derivatives: ∂f∂x,∂f∂y\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}

Geometry

  1. Closest Point on a Line

    • Line Equation: y=2x+1y = 2x + 1
    • Distance Minimization: Finding the point on the line closest to a given point.

Equations

  1. Characteristic Equation for Eigenvalues:
det⁡(A−λI)=0\det(A - \lambda I) = 0
  1. Eigenvalue Magnitude for Unitary Matrices:
∣α∣=1|\alpha| = 1
  1. Gradient Descent Update Rule:
xt+1=xt−ηt∂f∂xx_{t+1} = x_t - \eta_t \frac{\partial f}{\partial x}
yt+1=yt−ηt∂f∂yy_{t+1} = y_t - \eta_t \frac{\partial f}{\partial y}
  1. Quadratic Form:
Q(x,y,z)=[xyz]M[xyz]Q(x, y, z) = \begin{bmatrix} x & y & z \end{bmatrix} M \begin{bmatrix} x \\ y \\ z \end{bmatrix}
  1. Distance Minimization for Closest Point on a Line:
Minimize (x−x0)2+(y−y0)2 subject to y=2x+1\text{Minimize } \sqrt{(x - x_0)^2 + (y - y_0)^2} \text{ subject to } y = 2x + 1