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IIT M FOUNDATION DIPLOMA FN EXAM - 22 Dec 2024

MLF End Term14 questions40 marks6 MCQ · 6 MSQ · 2 SAFoundation / Diploma / forenoon
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  1. A is a positive definite matrix.
  2. A is singular matrix.
  3. A is a symmetric matrix.
  4. A is a negative definite matrix.
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  1. A is a unitary matrix.
  2. A is Hermitian matrix.
  3. Eigenvectors of A are orthogonal.
  4. Eigenvalues of A are real.
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Which of the following options is/are true ?
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Which of the following options is/are true?
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Q11SA3 marks
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Comprehension passage - the questions below it refer to this
Based on the above data, answer the given subquestions question figure
Q12MCQ2 marks
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Answer key

  1. Q1 (MCQ, 2 marks): C
  2. Q2 (MCQ, 3 marks): D
  3. Q3 (MCQ, 3 marks): A
  4. Q4 (MCQ, 3 marks): A
  5. Q5 (MSQ, 3 marks): A, C
  6. Q6 (MSQ, 3 marks): A, C
  7. Q7 (MSQ, 3 marks): B, C, D
  8. Q8 (MSQ, 3 marks): A, D
  9. Q9 (MSQ, 4 marks): A, C, D
  10. Q10 (MSQ, 4 marks): A, C
  11. Q11 (SA, 3 marks): 46
  12. Q12 (MCQ, 2 marks): C
  13. Q13 (MCQ, 3 marks): B
  14. Q14 (SA, 1 marks): 1

Concepts this paper tests

Auto-generated summary from the source site. Handy as a checklist; the lessons above explain each idea from scratch.

Here’s a structured summary of the core topics, concepts, principles, and equations essential for the Diploma Level: Machine Learning Foundations (Computer-Based Exam) based on the provided question paper. The exam heavily emphasizes probability, linear algebra, optimization, and convex analysis.



1. Probability & Random Variables

Key Concepts:

aX+bY∼N(aμX+bμY,a2σX2+b2σY2)aX + bY \sim N(a\mu_X + b\mu_Y, a^2\sigma_X^2 + b^2\sigma_Y^2)
FZ(z)=1−(1−z)2,0≤z≤1F_Z(z) = 1 - (1 - z)^2, \quad 0 \leq z \leq 1
fU,V(u,v)=12e−u,u≥0,−u≤v≤uf_{U,V}(u,v) = \frac{1}{2}e^{-u}, \quad u \geq 0, -u \leq v \leq u
Y∼N(aTμ,aTΣa)Y \sim N(a^T \mu, a^T \Sigma a)

Key Equations:

ConceptEquation
Linear combo of normalsaX+bY∼N(aμX+bμY,a2σX2+b2σY2)aX + bY \sim N(a\mu_X + b\mu_Y, a^2\sigma_X^2 + b^2\sigma_Y^2)
CDF of min⁡(X,Y)\min(X,Y) (Uniform)FZ(z)=1−(1−z)2F_Z(z) = 1 - (1 - z)^2
Joint PDF of U=X+Y,V=X−YU = X+Y, V = X-YfU,V(u,v)=12e−u,u≥0,−u≤v≤uf_{U,V}(u,v) = \frac{1}{2}e^{-u}, \quad u \geq 0, -u \leq v \leq u
Multivariate normal transformationY=aTX∼N(aTμ,aTΣa)Y = a^T X \sim N(a^T \mu, a^T \Sigma a)

2. Linear Algebra

Key Concepts:

rank(A)+nullity(A)=n\text{rank}(A) + \text{nullity}(A) = n

Key Equations:

ConceptEquation
Positive DefinitexTAx>0x^T A x > 0 for all x≠0x \neq 0
Rank-Nullityrank(A)+nullity(A)=n\text{rank}(A) + \text{nullity}(A) = n
Unitary MatrixA∗A=IA^* A = I
Eigenvalues of ATAA^T A and AATAA^TSame non-zero eigenvalues

3. Convex Analysis

Key Concepts:

θa+(1−θ)b∈S\theta a + (1 - \theta) b \in S
f(θx+(1−θ)y)≤θf(x)+(1−θ)f(y)f(\theta x + (1 - \theta) y) \leq \theta f(x) + (1 - \theta) f(y)

Key Equations:

ConceptEquation
Convex Setθa+(1−θ)b∈S\theta a + (1 - \theta) b \in S for θ∈[0,1]\theta \in [0,1]
Convex Functionf(θx+(1−θ)y)≤θf(x)+(1−θ)f(y)f(\theta x + (1 - \theta) y) \leq \theta f(x) + (1 - \theta) f(y)
Convex Examplesxln⁡xx \ln x, e2x+ye^{2x + y}, −ln⁡(xy)-\ln(xy)

4. Optimization

Key Concepts:

xk+1=xk−η∇f(xk)x_{k+1} = x_k - \eta \nabla f(x_k)
∇f=(2x−6,2y−8)  ⟹  (x,y)→(1.8,2.4)\nabla f = (2x - 6, 2y - 8) \implies (x,y) \rightarrow (1.8, 2.4)

Then, 10x+10y=4210x + 10y = 42 (but the answer was 46; likely a typo in the question).

min⁡f(x)s.t.gi(x)≤0,i=1,…,m\min f(x) \quad \text{s.t.} \quad g_i(x) \leq 0, i = 1, \dots, m

The KKT conditions require:

  1. Stationarity: ∇f(x)+∑λi∇gi(x)=0\nabla f(x) + \sum \lambda_i \nabla g_i(x) = 0.
  2. Primal Feasibility: gi(x)≤0g_i(x) \leq 0.
  3. Dual Feasibility: λi≥0\lambda_i \geq 0.
  4. Complementary Slackness: λigi(x)=0\lambda_i g_i(x) = 0.

    • For active constraints (gi(x)=0g_i(x) = 0), λi>0\lambda_i > 0.
    • Example: For f(x1,x2)=x12+x22f(x_1,x_2) = x_1^2 + x_2^2 with g1(x)=x1+x2−1≤0g_1(x) = x_1 + x_2 - 1 \leq 0 and g2(x)=−x1≤0g_2(x) = -x_1 \leq 0:
    • If the optimum is on x1+x2=1x_1 + x_2 = 1, then λ1>0\lambda_1 > 0 and λ2=0\lambda_2 = 0.
    • The minimum value is 0.50.5 (but the answer was 1; likely a miscalculation).

Key Equations:

ConceptEquation
Gradient Descentxk+1=xk−η∇f(xk)x_{k+1} = x_k - \eta \nabla f(x_k)
KKT Stationarity∇f(x)+∑λi∇gi(x)=0\nabla f(x) + \sum \lambda_i \nabla g_i(x) = 0
Complementary Slacknessλigi(x)=0\lambda_i g_i(x) = 0

5. Applications (Profit/Cost Optimization)

Key Concepts:

∇f(x)=λ∇g(x)\nabla f(x) = \lambda \nabla g(x)

Key Equations:

ConceptEquation
Lagrangian Condition∇f(x)=λ∇g(x)\nabla f(x) = \lambda \nabla g(x)


2. Linear Algebra

3. Convex Analysis & Optimization

4. Applications