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IIT M FOUNDATION DIPLOMA AN EXAM - 22 Dec 2024 MLF End Term 14 questions40 marks6 MSQ · 6 MCQ · 2 SA Foundation / Diploma / afternoon
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Q1 MSQ 3 marks select all that apply A is a positive definite matrix. A is not a singular matrix. A is not a symmetric matrix. A is a negative definite matrix.
Q2 MSQ 3 marks select all that apply A is not a unitary matrix. A is Hermitian matrix. Eigenvectors of A are orthogonal. Eigenvalues of A are not real.
Comprehension passage - the questions below it refer to this
Based on the above data, answer the given subquestions.
Normal(−2, 7) Normal(−2, 13) Normal(−2, 25) None of these
Answer key Q1 (MSQ, 3 marks): A, BQ2 (MSQ, 3 marks): C, DQ3 (MSQ, 3 marks): A, B, CQ4 (MSQ, 3 marks): A, CQ5 (MCQ, 2 marks): CQ6 (MCQ, 3 marks): BQ7 (SA, 1 marks): 1Q8 (MSQ, 4 marks): B, DQ9 (MSQ, 4 marks): A, CQ10 (MCQ, 3 marks): DQ11 (MCQ, 3 marks): AQ12 (MCQ, 3 marks): AQ13 (MCQ, 2 marks): CQ14 (SA, 3 marks): 92Concepts this paper tests Auto-generated summary from the source site. Handy as a checklist; the lessons above explain each idea from scratch.
Here’s a structured summary of core topics, concepts, principles, and equations essential for the exam, followed by Mermaid knowledge graphs to visualize relationships.
Core Topics & Key Concepts
1. Linear Algebra & Matrix Theory
Key Equations :
Eigenvalue equation: A v = λ v A \mathbf{v} = \lambda \mathbf{v} A v = λ v . Determinant properties: det ( A B ) = det ( A ) det ( B ) \det(AB) = \det(A)\det(B) det ( A B ) = det ( A ) det ( B ) , det ( A T A ) = det ( A A T ) \det(A^T A) = \det(A A^T) det ( A T A ) = det ( A A T ) . Rank-nullity theorem: rank ( A ) + nullity ( A ) = n \text{rank}(A) + \text{nullity}(A) = n rank ( A ) + nullity ( A ) = n .
2. Convexity & Optimization
Convex Sets :
A set S S S is convex if for any a , b ∈ S a, b \in S a , b ∈ S , θ a + ( 1 − θ ) b ∈ S \theta a + (1-\theta)b \in S θ a + ( 1 − θ ) b ∈ S for θ ∈ [ 0 , 1 ] \theta \in [0, 1] θ ∈ [ 0 , 1 ] . Examples: Midpoint (θ = 0.5 \theta = 0.5 θ = 0.5 ), linear combinations (e.g., 0.4 a + 0.6 b 0.4a + 0.6b 0.4 a + 0.6 b ).
Convex Functions :
f f f is convex if f ( θ x + ( 1 − θ ) y ) ≤ θ f ( x ) + ( 1 − θ ) f ( y ) f(\theta x + (1-\theta)y) \leq \theta f(x) + (1-\theta)f(y) f ( θ x + ( 1 − θ ) y ) ≤ θ f ( x ) + ( 1 − θ ) f ( y ) .Tests for Convexity :
Hessian ∇ 2 f ⪰ 0 \nabla^2 f \succeq 0 ∇ 2 f ⪰ 0 (positive semidefinite). Composition rules: If f f f is convex and g g g is convex + non-decreasing, then f ∘ g f \circ g f ∘ g is convex. Examples:
e x + y e^{x+y} e x + y is convex.x ln x x \ln x x ln x is convex for x > 0 x > 0 x > 0 .− ln ( x y ) -\ln(xy) − ln ( x y ) is not convex.
3. Probability & Statistics
Order Statistics :
For independent X , Y ∼ Uniform ( 0 , 1 ) X, Y \sim \text{Uniform}(0,1) X , Y ∼ Uniform ( 0 , 1 ) , Z = min ( X , Y ) Z = \min(X, Y) Z = min ( X , Y ) has CDF: F Z ( z ) = 1 − ( 1 − z ) 2 F_Z(z) = 1 - (1 - z)^2 F Z ( z ) = 1 − ( 1 − z ) 2 .
4. Gradient Descent
Update Rule : x k + 1 = x k − η ∇ f ( x k ) \mathbf{x}_{k+1} = \mathbf{x}_k - \eta \nabla f(\mathbf{x}_k) x k + 1 = x k − η ∇ f ( x k ) .Example : For f ( x , y ) = x 2 + y 2 − 6 x − 8 y f(x,y) = x^2 + y^2 - 6x - 8y f ( x , y ) = x 2 + y 2 − 6 x − 8 y , gradient: ∇ f = ( 2 x − 6 , 2 y − 8 ) \nabla f = (2x - 6, 2y - 8) ∇ f = ( 2 x − 6 , 2 y − 8 ) . After one iteration with η = 0.2 \eta = 0.2 η = 0.2 , ( x , y ) = ( 1 , 2 ) → ( 1.8 , 2.4 ) (x, y) = (1, 2) \rightarrow (1.8, 2.4) ( x , y ) = ( 1 , 2 ) → ( 1.8 , 2.4 ) .
Key Equations Summary
Topic Equation Quadratic Form f ( x ) = x T A x f(\mathbf{x}) = \mathbf{x}^T A \mathbf{x} f ( x ) = x T A x Positive Definite x T A x > 0 \mathbf{x}^T A \mathbf{x} > 0 x T A x > 0 for all x ≠ 0 \mathbf{x} \neq 0 x = 0 Eigenvalue Equation A v = λ v A \mathbf{v} = \lambda \mathbf{v} A v = λ v KKT Stationarity ∇ f + ∑ λ i ∇ g i = 0 \nabla f + \sum \lambda_i \nabla g_i = 0 ∇ f + ∑ λ i ∇ g i = 0 Convex Combination θ a + ( 1 − θ ) b \theta a + (1-\theta)b θ a + ( 1 − θ ) b , θ ∈ [ 0 , 1 ] \theta \in [0, 1] θ ∈ [ 0 , 1 ] CDF of Min(X, Y) F Z ( z ) = 1 − ( 1 − z ) 2 F_Z(z) = 1 - (1 - z)^2 F Z ( z ) = 1 − ( 1 − z ) 2 (for Uniform(0,1))Linear Transformation Y = a X + b Y = aX + b Y = a X + b , Y ∼ N ( a μ + b , a 2 σ 2 ) Y \sim N(a\mu + b, a^2 \sigma^2) Y ∼ N ( a μ + b , a 2 σ 2 ) Gradient Descent Update x k + 1 = x k − η ∇ f ( x k ) \mathbf{x}_{k+1} = \mathbf{x}_k - \eta \nabla f(\mathbf{x}_k) x k + 1 = x k − η ∇ f ( x k )
2. Convexity & Optimization
3. Probability & Statistics
4. Gradient Descent
Exam Tips
Matrix Properties : Focus on positive definiteness, eigenvalues, and symmetry.Convexity : Remember tests for convex functions (Hessian, composition rules).KKT Conditions : Memorize the 4 conditions and when λ i > 0 \lambda_i > 0 λ i > 0 .Probability : Practice transformations (e.g., U = X + Y U = X + Y U = X + Y , V = X − Y V = X - Y V = X − Y ) and order statistics.Gradient Descent : Compute gradients carefully and apply the update rule step-by-step.