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IIT M DIPLOMA AN EXAM QDD2 23 Feb 2025 - 23 Feb 2025

MLF Quiz 114 questions40 marks8 MCQ · 4 MSQ · 2 SADiploma / afternoon / QDD2
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Q1MCQ3 marks
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  1. 0.162
  2. 0.257
  3. 0.157
  4. 1.57
Q2MCQ3 marks
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  1. Eigenvectors corresponding to the two different eigenvalues of M areorthogonal.
  2. The matrix M is not diagonalizable.
  3. The eigenvalues of M are 4 and 1
  4. The rank of M is 1.
Q3MCQ3 marks
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Q4MCQ3 marks
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Q5MSQ3 marksselect all that apply
Which of the following options is/are true?
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Q6MSQ3 marksselect all that apply
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Q7MSQ3 marksselect all that apply
Which of the following statements is/are correct?
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Q8MSQ2 marksselect all that apply
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Q9SA2 marks
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Q10SA3 marks
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Comprehension passage - the questions below it refer to this
Based on the above data, answer the given subquestions. question figure
Q11MCQ3 marks
For the input x = [0.9, 5, 1], what will be the predicted output u(z)?
  1. 0
  2. 1
  3. 1.75
  4. Cannot be determined
Q12MCQ3 marks
If the threshold in the step function is changed to z ≥ 1.0, what will happen to the misclassification rate?
  1. Increase
  2. Decrease
  3. Remain same
  4. Cannot be determined
Comprehension passage - the questions below it refer to this
Based on the above data, answer the given subquestions. question figure
Q13MCQ3 marks
If B is diagonalizable, what is the invertible matrix P such that B = PDP−1?
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Q14MCQ3 marks
If B is diagonalizable, which of the following is a diagonal matrix D such that B = PDP−1? Use the matrix P obtained in the previous question.
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Answer key

  1. Q1 (MCQ, 3 marks): C
  2. Q2 (MCQ, 3 marks): D
  3. Q3 (MCQ, 3 marks): A
  4. Q4 (MCQ, 3 marks): B
  5. Q5 (MSQ, 3 marks): A, D
  6. Q6 (MSQ, 3 marks): B, C
  7. Q7 (MSQ, 3 marks): B, C, D
  8. Q8 (MSQ, 2 marks): A, B, C
  9. Q9 (SA, 2 marks): 15
  10. Q10 (SA, 3 marks): 6.37 to 6.43
  11. Q11 (MCQ, 3 marks): B
  12. Q12 (MCQ, 3 marks): A
  13. Q13 (MCQ, 3 marks): D
  14. Q14 (MCQ, 3 marks): A

Concepts this paper tests

Auto-generated summary from the source site. Handy as a checklist; the lessons above explain each idea from scratch.

Summary of Core Topics, Concepts, Principles, and Equations

1. Linear Approximation

L(x,y)=f(a,b)+fx(a,b)(x−a)+fy(a,b)(y−b)L(x, y) = f(a, b) + f_x(a, b)(x - a) + f_y(a, b)(y - b)

2. Matrix Properties

3. Directional Derivative

Duf(x0,y0)=∇f(x0,y0)⋅uD_{\mathbf{u}} f(x_0, y_0) = \nabla f(x_0, y_0) \cdot \mathbf{u}

4. Least Squares Method

min⁡θ0,θ1,θ2∑i=1n(yi−(θ0+θ1xi+θ2xi2))2\min_{\theta_0, \theta_1, \theta_2} \sum_{i=1}^{n} \left( y_i - (\theta_0 + \theta_1 x_i + \theta_2 x_i^2) \right)^2

5. Vector Projection

projba=(a⋅bb⋅b)b\text{proj}_{\mathbf{b}} \mathbf{a} = \left( \frac{\mathbf{a} \cdot \mathbf{b}}{\mathbf{b} \cdot \mathbf{b}} \right) \mathbf{b}

6. Continuity and Differentiability

7. Gradient and Length

∇f=(∂f∂x,∂f∂y,∂f∂z)\nabla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right)

The length of the gradient is:

∥∇f∥=(∂f∂x)2+(∂f∂y)2+(∂f∂z)2\|\nabla f\| = \sqrt{\left( \frac{\partial f}{\partial x} \right)^2 + \left( \frac{\partial f}{\partial y} \right)^2 + \left( \frac{\partial f}{\partial z} \right)^2}

8. Classification Model

u(z)={1if z≥threshold0otherwiseu(z) = \begin{cases} 1 & \text{if } z \geq \text{threshold} \\ 0 & \text{otherwise} \end{cases}

9. Diagonalization