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IIT M FOUNDATION DIPLOMA AN EXAM - 22 Dec 2024

MLF End Term14 questions40 marks6 MSQ · 6 MCQ · 2 SAFoundation / Diploma / afternoon
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Q1MSQ3 marksselect all that apply
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  1. A is a positive definite matrix.
  2. A is not a singular matrix.
  3. A is not a symmetric matrix.
  4. A is a negative definite matrix.
Q2MSQ3 marksselect all that apply
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  1. A is not a unitary matrix.
  2. A is Hermitian matrix.
  3. Eigenvectors of A are orthogonal.
  4. Eigenvalues of A are not real.
Q3MSQ3 marksselect all that apply
Which of the following options is/are true ?
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Q4MSQ3 marksselect all that apply
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Comprehension passage - the questions below it refer to this
Based on the above data, answer the given subquestions. question figure
Q5MCQ2 marks
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Q6MCQ3 marks
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Q7SA1 mark
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Q8MSQ4 marksselect all that apply
Which of the following options is/are true?
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Q9MSQ4 marksselect all that apply
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Q10MCQ3 marks
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Q11MCQ3 marks
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Q12MCQ3 marks
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Q13MCQ2 marks
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  1. Normal(−2, 7)
  2. Normal(−2, 13)
  3. Normal(−2, 25)
  4. None of these
Q14SA3 marks
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Answer key

  1. Q1 (MSQ, 3 marks): A, B
  2. Q2 (MSQ, 3 marks): C, D
  3. Q3 (MSQ, 3 marks): A, B, C
  4. Q4 (MSQ, 3 marks): A, C
  5. Q5 (MCQ, 2 marks): C
  6. Q6 (MCQ, 3 marks): B
  7. Q7 (SA, 1 marks): 1
  8. Q8 (MSQ, 4 marks): B, D
  9. Q9 (MSQ, 4 marks): A, C
  10. Q10 (MCQ, 3 marks): D
  11. Q11 (MCQ, 3 marks): A
  12. Q12 (MCQ, 3 marks): A
  13. Q13 (MCQ, 2 marks): C
  14. Q14 (SA, 3 marks): 92

Concepts this paper tests

Auto-generated summary from the source site. Handy as a checklist; the lessons above explain each idea from scratch.

Here’s a structured summary of core topics, concepts, principles, and equations essential for the exam, followed by Mermaid knowledge graphs to visualize relationships.


Core Topics & Key Concepts

1. Linear Algebra & Matrix Properties

A=[110150003]A = \begin{bmatrix} 1 & 1 & 0 \\ 1 & 5 & 0 \\ 0 & 0 & 3 \end{bmatrix}

2. Convexity


3. Optimization & KKT Conditions


4. Probability & Statistics

fU,V(u,v)=fX,Y(x,y)⋅∣J∣−1,J=∣∂u∂x∂u∂y∂v∂x∂v∂y∣f_{U,V}(u,v) = f_{X,Y}(x,y) \cdot |J|^{-1}, \quad J = \begin{vmatrix} \frac{\partial u}{\partial x} & \frac{\partial u}{\partial y} \\ \frac{\partial v}{\partial x} & \frac{\partial v}{\partial y} \end{vmatrix}
FZ(z)=1−(1−z)2,0≤z≤1.F_Z(z) = 1 - (1 - z)^2, \quad 0 \leq z \leq 1.
Y∼N(aTμ,aTΣa).Y \sim N(a^T \mu, a^T \Sigma a).
aX+bY∼N(aμ1+bμ2,a2σ12+b2σ22).aX + bY \sim N(a\mu_1 + b\mu_2, a^2\sigma_1^2 + b^2\sigma_2^2).

5. Gradient Descent

x(k+1)=x(k)−η∇f(x(k)).\mathbf{x}^{(k+1)} = \mathbf{x}^{(k)} - \eta \nabla f(\mathbf{x}^{(k)}).
x(1)=1−0.2(2⋅1−6)=1.8,y(1)=2−0.2(2⋅2−8)=2.8.x^{(1)} = 1 - 0.2(2 \cdot 1 - 6) = 1.8, \quad y^{(1)} = 2 - 0.2(2 \cdot 2 - 8) = 2.8.

2. Convexity & Optimization

3. Probability & Transformations

4. Gradient Descent Workflow


Key Equations Summary

TopicEquation
Quadratic Formf(x)=xTAx=∑i,jAijxixjf(\mathbf{x}) = \mathbf{x}^T A \mathbf{x} = \sum_{i,j} A_{ij} x_i x_j
Positive DefinitexTAx>0\mathbf{x}^T A \mathbf{x} > 0 for all x≠0\mathbf{x} \neq 0
KKT Stationarity∇f+∑λi∇gi=0\nabla f + \sum \lambda_i \nabla g_i = 0
Jacobian TransformationfU,V(u,v)=fX,Y(x,y)⋅∣J∣−1f_{U,V}(u,v) = f_{X,Y}(x,y) \cdot |J|^{-1}
Min of Uniforms CDFFZ(z)=1−(1−z)2F_Z(z) = 1 - (1 - z)^2
Linear Combination NormaX+bY∼N(aμX+bμY,a2σX2+b2σY2)aX + bY \sim N(a\mu_X + b\mu_Y, a^2\sigma_X^2 + b^2\sigma_Y^2)
Gradient Descentx(k+1)=x(k)−η∇f(x(k))\mathbf{x}^{(k+1)} = \mathbf{x}^{(k)} - \eta \nabla f(\mathbf{x}^{(k)})