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Here’s a structured summary of core topics, concepts, principles, and equations essential for this exam, followed by Mermaid knowledge graphs to visualize relationships.
Core Topics & Key Concepts
1. Probability & Random Variables
Distributions:
Normal Distribution: X∼N(μ,σ2).
Linear combinations: If X∼N(μX,σX2) and Y∼N(μY,σY2), then aX+bY∼N(aμX+bμY,a2σX2+b2σY2).
Key Equation:
W=3X+2Y∼N(3μX+2μY,9σX2+4σY2)
Uniform Distribution: X∼Uniform(a,b).
CDF of min(X,Y): For independent X,Y∼Uniform(0,1),
FZ(z)=1−(1−z)2,0≤z≤1
Exponential Distribution: Joint PDF fX,Y(x,y)=e−(x+y) for x,y≥0.
Transformation of Variables: For U=X+Y, V=X−Y, the joint PDF is:
fU,V(u,v)=21e−u,u≥0,−u≤v≤u
Multivariate Normal Distribution:
X∼N(μ,Σ). For Y=aTX, Y∼N(aTμ,aTΣa).
Key Equation:
Y=−x1+2x3∼N(−1⋅1+2⋅3,(−102)Σ−102)
=N(5,31)
2. Linear Algebra
Matrix Properties:
Positive Definite: A is positive definite if xTAx>0 for all x=0.
Symmetric Matrix: A=AT.
Quadratic Forms: f(x)=xTAx. For f(x)=x12+2x1x2+5x22+3x32, A is:
A=110150003
(Symmetric and positive definite.)
Eigenvalues/Eigenvectors:
Unitary Matrix: A∗A=I. For complex matrices, check A∗=A−1.
Hermitian Matrix: A=A∗. Eigenvalues are real; eigenvectors are orthogonal.
Key Facts:
Non-zero eigenvalues of ATA and AAT are identical.
det(A)=0 implies nullity =0 (no zero eigenvalues).
Full-rank A has rank(A)=n.
3. Convexity & Optimization
Convex Sets:
A set S is convex if λa+(1−λ)b∈S for all a,b∈S, λ∈[0,1].
Examples: Midpoint (0.5a+0.5b) and 0.7a+0.3b are in S.
Convex Functions:
f is convex if f(λx+(1−λ)y)≤λf(x)+(1−λ)f(y).
Examples:
f(x)=xlnx (convex on [0,∞)).
f(x,y)=e2x+y (convex, as Hessian is positive semidefinite).
f(x,y)=−ln(xy) (convex on (0,∞)2).
Composition: If f is convex and non-decreasing, and g is convex, then f∘g is convex.
Optimization Algorithms:
Gradient Descent: Update rule:
xk+1=xk−η∇f(xk)
Example: For f(x,y)=x2+y2−6x−8y, ∇f=(2x−6,2y−8). Starting at (1,2), first iteration:
x1=1−0.2(2⋅1−6)=1.8,y1=2−0.2(2⋅2−8)=2.8
10x+10y=46.
KKT Conditions:
For constrained optimization minf(x) s.t. gi(x)≤0, KKT requires:
Stationarity: ∇f(x)+∑λi∇gi(x)=0.
Primal Feasibility: gi(x)≤0.
Dual Feasibility: λi≥0.
Complementary Slackness: λigi(x)=0.
Example: For f(x1,x2)=x12+x22 with g1=x1+x2−1≤0, g2=−x1≤0, optimal (x1,x2) satisfies:
∇f+λ1∇g1+λ2∇g2=0
If on boundary x1+x2=1, then λ1>0, λ2=0.
4. Applications
Profit Maximization:
Use Lagrange multipliers for constrained optimization.